My Gr 2 headmaster in the village would let us out for recess if only we recite our multiplication tables. Those were the times. Here, is a strategy and if used properly can be very effective too.
I'd like to called it 'Collective Summation'. It uses the idea of patterns and simple multiplication & addition.
Students can easily recall the first 5 multiples of 4
4 x 1 = 4
4 x 2 = 8......I will us this to show the strategy
4 x 3 = 12
4 x 4 = 16
4 x 5 = 20
Strategy 1
Key: remember the last multiple and add 4.
4 x 2 = 8
then 4 x 3 = 12 = 4 + 8
4 x 4 = 16 = 4 + 12
4 x 5 = 20 = 4 + 16
Instead of responsive recall of multiples of 4, what you are doing is actually working with what you know and adding a 4 to the subsequent number to get the next.
This strategy can be applied to hard-to-recall multiples in 6, 7, 8 and 13 times tables.
---------------------------
Strategy 2
Using square numbers:
4 = 2 x 2
9 = 3 x 3
16 = 4 x 4
25 = 5 x 5
36 = 6 x 6
49 = 7 x 7
64 = 8 x 8
81 = 9 x 9
100 = 10 x 10
121 = 11 x 11
144 = 12 x 12
169 = 13 x 13
If you know, you can easily work out the multiples, when these numbers are doubled.
2 x 2 = 4 2 x 4 = 8 = 4 + 4
3 x 3 = 9 3 x 6 = 18 = 9 + 9
-----------------------------------------
16 = 4 x 4 4 x 8 = 32 = 16 + 16
25 = 5 x 5 5 x 10 = 50 = 25+ 25
36 = 6 x 6 6 x 12 = 72 = 36 + 36
49 = 7 x 7 7 x 14 = 58= 49 + 49
Got the idea? Now, try these
64 = 8 x 8 8 x 16 =
81 = 9 x 9 9 x 18 =
100 = 10 x 10 10 x 20 =
121 = 11 x 11 11 x 11 =
144 = 12 x 12 12 x 24 =
169 = 13 x 13 13 x 26 =
Teacher's Note: You may have a technique you have used in class over time - this is what I personally find useful. It can give your students confidence in you, too. (You know what I mean when you cannot do 12 x 24 in front of your student :))
Students' Note: You will find this useful when doing calculation involving 12 x 12, 12 x 24, 13 x 13 and 13x 26. It can save you lots of exam time.
------------------
Perimeter | Finding a missing length
The diagram shows a rectangle and a square.
Solution.........perimeter, p, is the sum of lengths around a shape
rectangle, p = 8+8+2+2 = 20 cm
square, s = 20/4 = 5 cm ....4 is the number of equal sides in a square
-----------------
Students note
- showing a clear working out will result in awarding of full marks
- key to getting this question right is knowing how to find perimeter and 4 sides of a square are equal.
Teachers note
- students should know the formulae p = 2( l + w) and p = 4s, for rectangle and square respectively. But, I think the best strategy is to show students the concept, not formula, as the concept can be used in both regular and irregular shapes. Remembering to use formulae can create confusion in contextual exam setting if a student can not recall them easily.
The perimeter of the rectangle is the same as the
perimeter of the square.
Work out the length of one side of the rectangle.Solution.........perimeter, p, is the sum of lengths around a shape
Perimeter | Adding the lengths by collecting like terms
In the diagram, all measurements are
given in centimetres.
perimeter = side 1 + side 2 + side 3 + ...... (two sides are missing)
= 2x + x + 3 + 2 + horizontal missing side + vertical missing side
= 2x + x + 3 + 2 + 2x + 3 + x + 2
= 6x + 10
= 2(3 + 10) ......you've got to factorise to show
------------------------------*
Note: to get 4 full marks for this question, student must show (by calculation).
All angles are right angles.
Show that the perimeter of the shape can be written as
2(3x + 5).
----------------------------
Solution
Prime Number, Square Number, Sequence
Here
are 5 rows of numbers.
Row
A
|
2
|
4
|
6
|
8
|
10
|
12
|
14
|
16
|
Row
B
|
3
|
5
|
7
|
9
|
11
|
13
|
15
|
17
|
Row
C
|
2
|
3
|
5
|
7
|
11
|
13
|
17
|
Row
D
|
1
|
2
|
5
|
10
|
20
|
50
|
100
|
200
|
Row
E
|
1
|
2
|
4
|
8
|
16
|
32
|
64
|